If `n_(2)` moles of non-volatile solute are dissolved in `n_(1)` moles of the solvent, Raoult's law is expressed mathematically as

When one mole of non-volatile solute is dissolved in three moles of solvent, the vapour pressure of the solution relative to the vapour pressure of the pure solvent is -

One mole of non-volatile solute is dissolved in two moles of water. The vapour pressure of the solution relative to that water of

If to a solvent (vapour pressure =p^(@)) , n moles of a non volatile solute are dissolved then the vapour pressure of the solution p is

One mole on non-volatile solute is dissolved in two mole of water. The vapour pressure of the solution relative to that of water is:

One mole of non-volatile solute is dissolved in two mole of water. The vapour pressure of the solution relative to that of water is:

n moles of a non volatile solute are dissolved in wg of water. If K_(f) is the molal depression constant of water, the freezing point of the solution will be