The solutions of the equation `z^4 + 4i z^3 - 6z^2 - 4iz -i =0 ` represent vertices of a convex polygon in the complex plane. The area of the polygon is :

The area of the triangle in the complex plane formed by the points z, iz and z+iz is

If all the complex numbers z such that |z| = 1 and |(z)/(barz)+(barz)/(z)| = 1 are vertices of a polygon then the area of the polygon is K so [2k] is equals ( [.] denotes G.I.F.)

The area of the triangle in the complex plane formed by z, iz and z +iz is

If the complex numbers iz,z and z+iz represent the three vertices of a triangle,then the area of the triangle is

The equation of the radical axis of the two circles represented by the equations,|z-2|=3 and |z-2-3i|=4 an the complex plane is

If the imaginary part of (2z + 1)/(iz + 1) is -4, then the locus of the point representing z in the complex plane is

If z = x + yi, omega = (2-iz)/(2z-i) and |omega|=1 , find the locus of z in the complex plane

The points z_1, z_2, z_3, z_4 in the complex plane form the vertices of a parallelogram iff :