Coefficient of friction between A and B is `mu` . The minimum force F with which A will be pushed such that B will not slip down is -

If the coefficient of friction between A and B is mu , the maximum acceleration of the wedge A for which B will remain at rest with respect to the wedge is

If the coefficient of friction between A and B is mu , the maximum acceleration of the wedge A for which B will remain at rest with respect to the wedge is

If the coefficient of friction between A and B is mu , the maximum acceleration of the wedge A for which B will remain at rest with respect to the wedge is

In Fig. 7.149 , coefficient of friction between the block and the floor is mu . Force F that will move the block on the floor with a uniform speed is :

Mas of man is 'm' There is no friction between man and black But 'mu' is coefficient of friction between block and floor. Maximum force that the man can exert on the rope so that the block does not slip on floor

The mass of block A is 100 kg and that of block B is 200 kg. The coefficient of friction between A and B is 0.2 and that between B and ground level is 0.3. The minimum force which will make the block B move, will be:

Block B rests on a smooth surface .The coefficient of static friction between A and B is mu = 0.4 where F = 30 N then Acceleration of upper block is

Block B rests on a smooth surface .The coefficient of static friction between A and B is mu = 0.4 where F = 30 N then Acceleration of upper block is

Block B rests on a smooth surface .The coefficient of static friction between A and B is mu = 0.4 where F = 30 N then Acceleration of lower block is

Wedge is fixed on horizontal surface. Block A is pulled upward by applying a force F as shown in figure and there is no friction between the wedge and the block A while coefficient of friction between A and B is mu . If there is no relative motion between the block A and B then frictional force developed between A and B is