Five forces `vec(F)_(1) ,vec(F)_(2) , vec(F)_(3) , vec(F)_(4)` , and `vec(F)_(5)` , are action on a particle of mass `2.0kg` so that is moving with `4m//s^(2)` in east direction. If `vec(F)` force is removed, then the acceleration become `7m//s^(2)` in north, then the acceleration of the block if only `vec(F)` is action will be:

Five forces vec(F)_(1) ,vec(F)_(2) , vec(F)_(3) , vec(F)_(4) , and vec(F)_(5) , are acting on a particle of mass 2.0kg so that is moving with 4m//s^(2) in east direction. If vec(F)_(1) force is removed, then the acceleration becomes 7m//s^(2) in north, then the acceleration of the block if only vec(F)_(1) is action will be:

When force vec(F)_(1),vec(F)_(2),vec(F)_(3) are acting on a particle of mass m , the particle remains in equilibrium. If the force vec(F)_(1) is now removed then the acceleration of the particle is :

When force vec(F_(1)), vec(F_(2)),vec(F_(3))"…..."vec(F_(n)) act on a particle , the particle remains in equilibrium . If vec( F_(1)) is now removed then acceleration of the particle is

Two forces vec(F_(1)) and vec(F_(2)) are acting at right angles to each other , find their resultant ?

Find the resultant of vec(F_(1)) + vec(F_(2)) - vec(F_(3)) ( sin 37^(@) = (3)/(5) , cos 37^(@) = (4)/(5))

A moving particle of mass m is acted upon by five forces vec(F)_(1),vec(F)_(2),vec_(F)_(3),vec(F)_(4) and vec(F)_(5 . Forces vec(F)_(2) and vec(F)_(3) are conservative and their potential energy functions are U and W respectively. Speed of the particle changes from V_(a) to V_b when it moves from position a to b. Which of the following statement is/are true – (a) Sum of work done by vec(F)_(1),vec(F)_(4) and vec(F)_(5)=U_(b)-U_(a)+W_(b)-W_(a) (b) Sum of work done by vec(F)_(1),vec(F)_(4) and vec(F)_(5)=U_(b)-U_(a)+W_(b)-W_(a)+1/2m(V_(a)^(2)-V_(a)^(2)) (c) Sum of work done by all five forces =1/2m(V_(b)^(2)-V_(a)^(2)) (d) Sum of work done by vec(F)_(2) and vec(F)_(3)=(U_(b)+W_(b))-(U_(a)+W_(a))

If the direction of position vector vec r is towards south and direciton of force vector vec F is towards east, then the direction of torque vector vec tau is

Three forces vec(F)_(1), vec(F)_(2) and vec(F)_(3) are represented as shown. Each of them is equal magnitude. Now match the given columns and select the correct option from the codes given below.