Linear momentum of an object can be expressed as `vecP= (4 cos t)hati+( 4 sin t)hatj`. Angle between the forces acting on the object and its linear momentum is :

The momentum of a body is vec P =2 cos t hati +2 sin t hatj. What is the angle between the force vec F acting on the body and the momentum vec P ?

The momentum of a particle is vecP=costhetahati+sinthetahatj . The angle between momentum and the force acting on a body is

Newton's.. . law of motion shows the relation between external force acting on the object and change in its momentum.

in a circular motion the angle between a particle's linear momentum and its angular moment is

At the instant the displacement of a 1.50 kg object relative to the origin is vecd=(2.00m)hati+(4.00m)hatj-(3.00m//s)hatk , its velocity is vecv=-(6.00m//s)hati+(3.00m//s)hatj+(3.00m)hatk and it is subject to a force vecF=(6.00N)hati-(8.00N)hatj+(4.00N)hatk . Find (a) the acceleration of the object, (b) the angular momentum of the object about the origin, ( c) the torque about the origin acting on the object, and (d) the angle between the velocity of the object and the force acting on the object.

IF p is the magnitude of linear momentum of a particle executing a uniform circular motion, then the ratio of centripetal force acting on the particle to its linear momentum is given by

IF p is the magnitude of linear momentum of a particle executing a uniform circular motion, then the ratio of centripetal force acting on the particle to its linear momentum is given by