There are 3 different pairs `(i.e. 6 `units say `a, a, b, b, c, c)` of shoes in a lot. Now three person come & pick the shoes randomly (each gets 2 units). Let p be the probability that no one is able to wear shoes (i.e. no one gets a correct pain), then `(13p)/(4-p)`is

There are 10 pairs of shoes in a cupboard, from which 4 shoes are picked at random. If p is the probability that there is at least one pair, then 323p-97 is equal to

Three players A, B, C toss a coin in turn till head shows. Let p be the probability that the coin shows a head. Let alpha,beta,gamma be respectively the probabilities that A, B and C get first head then

From a heap containing 10 pairs of shoes 6 shoes are selected at random. Find the probability that (i) There is no complete pair in the selected shoes (ii) atleast one correct pair in the selected shoes (iii) 2 correct pairs in the selected shoes.

Three player A, B and C , toss a coin cyclically in that order (that is A, B, C, A, B, C, A, B,... ) till a headshows. Let p be the probability that the coin shows a head. Let alpha, beta and gamma be, respectively, the probabilities that A, B and C gets the first head. Then determine alpha, beta and gamma (in terms of p).

Three player A, B and C , toss a coin cyclically in that order (that is A, B, C, A, B, C, A, B,... ) till a headshows. Let p be the probability that the coin shows a head. Let alpha, beta and gamma be, respectively, the probabilities that A, B and C gets the first head. Then determine alpha, beta and gamma (in terms of p).

If the events E_1, E_2,………….E_n are independent and such that P(E_i^C) = i/(i+1) , i=1, 2,……n, then find the probability that at least one of the n events occur.

For three events A ,B and C ,P (Exactly one of A or B occurs) =P (Exactly one of B or C occurs) =P (Exactly one of C or A occurs) =1/4 and P (All the three events occur simultaneously) =1/16dot Then the probability that at least one of the events occurs, is :

For three events A ,B and C ,P (Exactly one of A or B occurs) =P (Exactly one of B or C occurs) =P (Exactly one of C or A occurs) =1/4 and P (All the three events occur simultaneously) =1/16dot Then the probability that at least one of the events occurs, is :

For three events A ,B and C ,P (Exactly one of A or B occurs) =P (Exactly one of B or C occurs) =P (Exactly one of C or A occurs) =1/4 and P (All the three events occur simultaneously) =1/16dot Then the probability that at least one of the events occurs, is :