(a) At the moment `t=0`, a particle leaves the origin and moves in the positive direction of the x-axis. Its velocity is given by `v=10-2t`. Find the displacement and distance in the first `8s`.
(b) If `v=t-t^(2)`, find the displacement and distamce in first 2s.

At the moment t=0 particle leaves the origin and moves in the positive direction of the x-axis. Its velocity varies with time as v=10(1-t//5) . The dislpacement and distance in 8 second will be

At the moment t=0 a particle leaves the origin and moves in the positive direction of the x-axis.Its velocity at any time is vecv=vecv_0(1-t/tau) where v_0=10 cm/s and tau =5 s. Find : (a)the x-coordinates of the particle at the instant 6s, 10s and 20s. (b)the instant at which it is a distance 10 cm from the origin. (c )the distance s covered by the particle during the first 4s and 8s.

At the moment t=0 a particle leaves the origin and moves in the positive direction of the x-axis. Its velocity varies with time as v=v_0(1-t//tau) , where v_0 is the initial velocity vector whose modulus equals v_0=10.0cm//s , tau=5.0s . Find: (a) the x coordinate of the particle at the moments of time 6.0 , 10 , and 20s , (b) the moments of time when the particles is at the distance 10.0cm from the origion, (c) the distance s covered by the particle during the first 4.0 and 8.0s , draw the approximate plot s(t) .

A particle starts from origin at time t=0 and moves in positive x-direction. Its velocity v varies with times as v = 10that(i) cm/s. The distance covered by the particle in 8 s will be

If velocity of a particle is given by v=3t^(2)-6t +4 . Find its displacement from t=0 to 3 secs .

The displacement s of a particle at time t is given by s = t^3 -4 t^2 -5t. Find the velocity and acceleration at t=2 sec

Acceleration of a particle moving along the x-axis is defined by the law a=-4x , where a is in m//s^(2) and x is in meters. At the instant t=0 , the particle passes the origin with a velocity of 2 m//s moving in the positive x-direction. (a) Find its velocity v as function of its position coordinates. (b) find its position x as function of time t. (c) Find the maximum distance it can go away from the origin.

Acceleration of a particle moving along the x-axis is defined by the law a=-4x , where a is in m//s^(2) and x is in meters. At the instant t=0 , the particle passes the origin with a velocity of 2 m//s moving in the positive x-direction. (a) Find its velocity v as function of its position coordinates. (b) find its position x as function of time t. (c) Find the maximum distance it can go away from the origin.

The displacement of a particle along the x-axis is given by x=3+8t+7t^2 . Obtain its velocity and acceleration at t=2s .

The displacement of a particle along the x-axis is given by x=3+8t+7t^2 . Obtain its velocity and acceleration at t=2s .