An air capactior is connected to a battery. The effect of filling the space between the plates with a dielectric is to increase

An uncharged parallel plate capacitor is connected to a battery. The electric field between the plates is 10V/m. Now a dielectric of dielectric constant 2 is inserted between the plates filling the entries space. The electric field between the plates now is

An uncharged parallel plate capacitor is connected to a battery. The electric field between the plates is 10V/m. Now a dielectric of dielectric constant 2 is inserted between the plates filling the entries space. The electric field between the plates now is

While a capacitor remains connected to a battery, a dielectric slab is slipped between the plates. Then

While a capacitor remains connected to a battery and dielectric slab is applied between the plates, then

A parallel plate capacitor is connected to a battery and inserted a dielectric plate between the place of plates then which quantity increase

If in a parallel capacitor, which is connected to a battery we fill in whole space of its plates, then which of the following increases?

A parallel plate air condenser is charged and then disconnected from the charging battery. Now the space between the plates is filled with a dielectric then, it electric field strength between the plates

In the adjoining diagram two geometrically identical capacitors A and B are connected to a battery. Air is filled between the plates of C_(1) and a dielectric is filled between the plates of C_(2) , then -

In the adjoining diagram two geometrically identical capacitors A and B are connected to a battery. Air is filled between the plates of C_(1) and a dielectric is filled between the plates of C_(2) , then -