For the reaction, `Fe^(3+)+3e^(-) hArr Fe, E^(@)` is -0.036 volt and the standard electrode potential for `Fe^(3+)+e^(-) hArr Fe^(2+)` is 0.771 volt. Calculate the `E^(@)` for `Fe^(2+)+2e^(-) hArr Fe`.

Given E_(Fe^(3+)//Fe)^(@) = -0.36 V, E_(Fe^(2+)//Fe)^(@)= - 0.439V . The value of standard electrode potential for the change , Fe^(3+)+e^(-) rarr Fe^(2+) will be

The standard reduction for the following reactions are : Fe^(3+) + 3e^(-) rarr Fe with E^(@) = - 0.036 V Fe^(2+) + 2e^(-) rarr Fe with E^(@) = - 0.44 V What would be the standard electrode potential for the reaction Fe^(3+) + e^(-) rarr Fe^(2+) ?

Given that the standard reduction potentials E ^(0) of Fe^(+2)|Feis 0.26V and Fe ^(+3) |Fe is 0.76V respectively. The E ^(@)of Fe ^(+2)|Fe^(+3) is:

Given that the standard reduction potentials E ^(0) of Fe^(+2)|Feis 0.26V and Fe ^(+3) |Fe is 0.76V respectively. The E ^(@)of Fe ^(+2)|Fe^(+3) is:

Given, standard electrode potentials, {:(Fe^(3+)+3e^(-) rarr Fe,,,E^(@) = -0.036 " volt"),(Fe^(2+)+2e^(-)rarr Fe,,,E^(@) = - 0.440 " volt"):} The standard electrode potential E^(@) for Fe^(3+) + e^(-) rarr Fe^(2+) is :

Given, standard electrode potentials, {:(Fe^(3+)+3e^(-) rarr Fe,,,E^(@) = -0.036 " volt"),(Fe^(2+)+2e^(-)rarr Fe,,,E^(@) = - 0.440 " volt"):} The standard electrode potential E^(@) for Fe^(3+) + e^(-) rarr Fe^(2+) is :

Given, standard electrode potentials, {:(Fe^(3+)+3e^(-) rarr Fe,,,E^(@) = -0.036 " volt"),(Fe^(2+)+2e^(-)rarr Fe,,,E^(@) = - 0.440 " volt"):} The standard electrode potential E^(@) for Fe^(3+) + e^(-) rarr Fe^(2+) is :

What will be the standard electrode potential for the change, Fe^(3+)(aq)+e rarr Fe^(2+)(aq). Given : E_(Fe^(3+)|Fe)^(@)=-0.036V, E_(Fe^(2+)|Fe)^(@)=-0.439V

E_(Fe^(3+)//Fe)^(@)=-0.036V,E_(Fe^(2+)//Fe)^(@)=-0.0439V . The value of standard electrode potential for the change, Fe^(3+)(aq)+e^(-)toFe^(2+)(aq) will be