What is the energy released by fassion of 1 g of `U^(235)`? (Assume 200 Me V energy is liberated on fission of 1 nucleus)

The energy liberated on complete fission of 1 kg of ._92 U^235 is (Assume 200 MeV energy is liberated on fission of 1 nucleus).

Calculate the energy released by fission of 1 g of ._(92)^(235)U , assuming that an energy of 200 MeV is released by fission of each atom of .^(235)U . (Avogardo constant is = 6.023 xx 10^(26) kg mol^(-1) )

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

Calculate the energy released by the fission 1 g of .^(235)U in joule, given that the energy released per fission is 200 MeV . (Avogadro's number =6.023xx10^(23))