If A and B are two square matrices of the same order then `(A-B)^2` is (A) `A^2-AB-BA+B^2` (B) `A^2-2AB+B^2` (C) `A^2-2BA+B^2` (D) `A^2-B^2`

If A and B are square matrices of the same order then (A+B)^2=A^2+2AB+B^2 implies

If A and B are square matrices of the same order such that B=-A^(-1)BA, then (A+B)^(2)

If A and B are two square matrices such that B=-A^(-1)BA then (A+B)^(2)=

If A and B are square matrices of the same order such that A^(2)=A,B^(2)=B,AB=BA=0 , then__

If A and B are two square matrices of same order, then (A+B)^2=A^2+2AB+B^2 can hold if and only if

If A and B are square matrices of the same order,then (A+B)(A-B) is equal to A^(2)-B^(2)(b)A^(2)-BA-AB-B^(2)(c)A^(2)-B^(2)+BA-AB(d)A^(2)-BA+B^(2)+AB

If A and B be square matrices of the same order such that AB=BA, prove that : (A-B)^2 = A^2 - 2AB + B^2

If A and B are square matrices of the same order then (A+B)^2=A^2+2AB+B^2 implies (A) AB=0 (B) AB+BA=0 (C) AB=BA (D) none of these