An ideal gas with the adiabatic exponent `gamma` goes through a process `p = p_0 - alpha V`, where `p_0` and `alpha` are positive constants, and `V` is the volume. At what volume will the gas entropy have the maximum value ?

One mole an ideal gas whose adiabatic exponent equals gamma undergoes a process p = p_0 + alpha//V , where p_0 and alpha are positive constants. Find : (a) heat capacity of the gas as a function of its volume , (b) the internal energy of heat transferred to the gas, of its volume increased from V_1 to V_2 .

One mole of an ideal gas undergoes a process P=P_(0)-alphaV^(2) where alpha and P_(0) are positive constant and V is the volume of one mole of gas Q. When temperature is maximum, volume is

One mole of an ideal gas undergoes a process P=P_(0)-alphaV^(2) where alpha and P_(0) are positive constant and V is the volume of one mole of gas Q. When temperature is maximum, volume is

One mole of an ideal gas undergoes a process P=P_(0)-alphaV^(2) where alpha and P_(0) are positive constant and V is the volume of one mole of gas Q. When temperature is maximum, volume is

One mole of an ideal gas undergoes a process P=P_(0)-alphaV^(2) where alpha and P_(0) are positive constant and V is the volume of one mole of gas Q. The maximum attainable temperature is

One mole of an ideal gas undergoes a process P=P_(0)-alphaV^(2) where alpha and P_(0) are positive constant and V is the volume of one mole of gas Q. The maximum attainable temperature is

Find the minimum attainable pressure of ideal gas in the process T = T_0 + alpha V^2 , where T_0 and alpha positive constants, and V is the volume of one mole of gas. Draw the approximate p vs V plot of this process.

An ideal gas has adiabatic exponent gamma . It expands according to the law P = alpha V, where is alpha constant. For this process, the Bulk modulus of the gas is

One mole of an ideal gas with adiabatic exponent gamma undergoes the process (a) P=P_0+(alpha)/(V) (b) T=T_0+alphaV Find Molar heat capacity of the gas as a function of its volume.