The acceleration due to gravity on the surface of the moon is `(1)/(6)th` of that on the surface of earth and the diameter of the moon is one-fourth that of earth. The ratio of escape velocities on earth and moon will be

The acceleration due to gravity on the surface of the moon is one-sixth that on the earth. The radius of the moon is about one-fourth tha tof the earth. If v_(e) is the escape velocity on the surfaceo f the earth, then escape velocity on the surface of the moon will be

If acceleration due to gravity on the surface of moon is (1//5)^("th") that at the surface of the earth and radius of the moon is (1//4)^("th") that of the earth, then the ratio of the mass of the earth to mass of moon is

Calculate the acceleration due to gravity on the surface of moon if mass of the moon is 1/80 times that of the Earth and diameter of the moon is 1/4 times that of the Earth.

The value of acceleration due to gravity 'g' on the surface of the moon with radius 1/2 that of the earth and same mean density as that of the earth

The mass of the moon is 1/(80) th of that of the earth and the radius of the moon is 1/4 th of that of the earth. The ratio of the acceleration due to gravity on the moon and that on the earth is

The acceleration due to gravity on the moon is (1^(th))/(6) that on the earth. If the earth and the moon are assumed to have the same density, then the radius of the moon is