What energy is needed to split an alpha particle to piece? Given mass of `alpha` particle is 4.0039a.m.u, mass of proton=1.007825u and mass of neutron =1.008665u use `1a.m.u.=931MeV`

Calculate the binding energy per nucleon of "_3Li^7 nucleus. Given mass of "_3Li^7 nucleus = 7.01599 a.m.u., mass of proton =1.007825 a.m.u., mass of neutron = 1.008665 a.m.u. and 1 a.m.u. = 931.5 MeV

Find the binding energy of an alpha -particle from the following data. Mass of helium nulceus =4.001235 am u Mass of proton =1.007277 am u Mass of neutron =1.00866 am u (take 1 amu=931.4813 MeV) .

A fusion reaction consists of combining four protons into an alpha –particle. The mass of alpha –particle is 4.002603u and that of proton is 1.007825u, mass of electron is 0.00054466u.

A fusion reaction consists of combining four protons into an alpha –particle. The mass of alpha –particle is 4.002603u and that of proton is 1.007825u, mass of electron is 0.00054466u.

Calculate the binding energy per nucleon of "_20Ca^40 nucleus. Given mass of "_20Ca^40 nucleus = 39.962589 a.m.u., mass of proton = 1.007825 a.m.u., mass of neutron = 1.008665 a.m.u. and 1 a.m.u. = 931.5 MeV.

Calculate the binding energy per nucleon of ._26Fe^(56) nucleus. Given that mass of ._26Fe^(56)=55.934939u , mass of proton =1.007825u and mass of neutron =1.008665 u and 1u=931MeV .