Home
Class 12
CHEMISTRY
The vapour pressure of water at room tem...

The vapour pressure of water at room temperature is 23.8 mm Hg. The vapour pressure of an aqueous solution of sucrose with mole fraction 0.1 is equal to

Promotional Banner

Similar Questions

Explore conceptually related problems

The vapour pressure of water at room temperature is 30 mm of Hg. If the mole fraction of water in a solution of non volatile solute is 0.9, the vapour pressure of the solution will be :-

The vapour pressure of water at room temperature is 30 mm of Hg. If the mole fraction of the water is 0.9, the vapour pressure of the solution will be :

Benzene and toluene from an ideal solution. The vapour pressure of benzene at 55^(@) C is 400 mm Hg while the vapour pressure of toluene at 55^(@)C is 130 mm Hg. What is the vapour pressure of a solution consisiting of 0.5 mole fraction of benzene and 0.5 mole fraction of toluene at 55^(@)C ?

Vapour pressure of water at 20^C is 17.5 mm of Hg and lowering of vapour pressure of a sugar soluton is 0.061 mm of Hg. Calculate mole fraction of sugar and water.

The vapour pressure of a pure liquid A is 40 mm Hg at 310 K . The vapour pressure of this liquid in a solution with liquid B is 32 mm Hg . Mole fraction of A in the solution , if it obeys Raoult's law is :

Vapour pressure of pure water at 298 k is 23.8 mm Hg. Calculate the lowering of vapour pressure caused by adding 5g of sucrose in 50 g of water.

Vapour pressure of pure water at 298 k is 23.8 mm Hg. Calculate the lowering of vapour pressure caused by adding 5g of sucrose in 50 g of water.