Recommended Questions
- Find the value of .^n Cr +.^(n-1) Cr + ......+ .^r Cr
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- If .^(n-1)Cr:^nCr:^(n+1)Cr=6:9:13 find n and r.
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- n(Cr) +(n-1)(C(r-1)) +(n-1)(C(r - 2)) = (n+1)(Cr)
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- Prove that ""^(n)Cr + ""^(n)C(r-1) = ""^(n+1)Cr
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- sum(r = 0)^(n-1) (Cr)/(Cr + C(r+1)) =
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- sum(r=0)^(r-1) (.^n Cr)/(.^n Cr + .^n C(r+1)) का मान है
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- .^n Cr + .^(n-1)Cr +….+.^r Cr=
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- यदि .^n Pr = 720. .^n Cr तब r का मान होगा
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- Prove that .(r+1)*^n Cr-r*^n Cr+ ... +(-1)^r.^n Cr=(-1)^r.^(n-2)Crdot
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