In the given figure, D is a point on side BC of a `DeltaABC` and E is a point such that CD = DE.
Prove that `AB+ACgtBE`.

In the given figure, D is a point on side BC of DeltaABC such that (BD)/(CD)=(AB)/(AC) . Prove that AD is the bisector of /_BAC .

In the given figure, D and E are points on the side BC of a DeltaABC such that BD = CE and AD = AE. Show that DeltaABD~=DeltaACE.

In triangle ABC, D is a point in side AB such that AB = 4AD and E is a point in AC such that AC = 4AE. Show that BC : DE = 4:1

In the given figure, D is mid-point of side AB of triangleABC and BDEC is a parallelogram. Prove that : Area of DeltaABC = Area of ////gmBDEC

In Figure,AC>AB and D is the point on AC such that AB=AD. Prove that BC>CD

In DeltaABC, AB = AC and D is a point in BC so that BD=CD . Prove that AD bisects angleBAC .

In DeltaABC, AB = AC and D is a point in BC so that BD=CD . Prove that AD bisects angleBAC .

In Fig .D is a point on side BC of DeltaABC such that (BD)/(CD) =(AB)/(AC) prove that AD is the bisector of angleBAC.

D and E are points on sides AB and AC respectively of DeltaABC such that ar (DBC) = ar (EBC). Prove that DE II BC .

In the given figure D is mid-point of AB. DE//BC and DF //AC . Prove that : DE = BF