In the given figure, P is the mid-point of side BC of a parallelogram ABCD such that `angleBAP=angleDAP.` Prove that AD = 2CD.

In figure, P is the mid-point of side BC of a parallelogram ABCD such that angleBAP=angleDAP . Prove that AD = 2CD.

In figure, P is the mid-point of side BC of a parallelogram ABCD such that angleBAP=angleDAP . Prove that AD = 2CD. ltBrgt

In fig. P is the mid point of side BC of a parallelogram ABCD such that angleBAP=angleDAP prove that AD=2CD

In the following figure, M is mid-point of BC of a parallelogram ABCD. DM intersects the diagonal AC at P and AB produced at E. Prove that : PE = 2 PD .

In the given figure, D is a point on side BC of DeltaABC such that (BD)/(CD)=(AB)/(AC) . Prove that AD is the bisector of /_BAC .

The mid-point of side CD of parallelogram ABCD is 'm' in the given figure what is the ratio ON : OB?

E is the mid-point of side AB and F is the mid point of side DC of parallelogram ABCD . Prove that AEFD is a parallelogram.

If E is a point on side AD produced of a parallelogram ABCD and BE intersects CD at F . Prove that DABE^(-)DCFB