Let f(x) `= [x]^(2) + [x+1] - 3`, where [.] denotes the greatest integer function. Then

If f(x)=[2x], where [.] denotes the greatest integer function,then

Let f(x) = [x^3 - 3] where [.] denotes the greatest integer function Then the number of points in the interval ( 1, 2) where the function is discontinuous, is

Let f(x)=sec^(-1)[1+cos^(2)x], where [.] denotes the greatest integer function. Then the

Let f(x)=sec^(-1)[1+cos^(2)x], where [.] denotes the greatest integer function. Then the

Let f(x)=sec^(-1)[1+cos^(2)x], where [.] denotes the greatest integer function. Then the range of f(x) is

Let f(x) = 1 + |x|,x = -1, where [*] denotes the greatest integer function.Then f { f (- 2.3)} is equal to

Let f(x)=[x]cos ((pi)/([x+2])) where [ ] denotes the greatest integer function. Then, the domain of f is

Let f(x)=|x| and g(x)=[x] , (where [.] denotes the greatest integer function) Then, (fog)'(-1) is

Let f(x)=|x| and g(x)=[x] , (where [.] denotes the greatest integer function) Then, (fog)'(-1) is

Let f(x)=cos x and g(x)=[x+1],"where [.] denotes the greatest integer function, Then (gof)' (pi//2) is