The minimum value of acceleration of wedge for which the block start sliding on the wedge, is:

A block of mass m is placed on a wedge of mass M. Coefficient of friction between them is mu gt cot theta. The minimum acceleration of the wedge at which block appears stationary relative to wedge is

A block of mass m is placed at the top of a smooth wedge ABC. The wedge is rotated about an axis passing through C as shown in the figure - 3.81. The minimum value of angular speed omega such that the block does not slip on the wedge is :

A block of mass m is placed at the top of a smooth wedge ABC. The wedge is rotated about an axis passing through C as shown in the figure - 3.81. The minimum value of angular speed omega such that the block does not slip on the wedge is :

A block of mass 5 kg is kept against an accelerating wedge with a wedge angle of 45^(@) to the horizontal. The coefficient of friction between the block and the wedge is mu = 0.4 . What is the minimum absolute value of the acceleration of the wedge to keep the block steady? [Assume, g = 10 m/s^(2) ]

Find the minimum acceleration of the wedge so that block under free fall

A block of mass m is pushed towards a movable wedge of mass nm and height h , with a velocity u . All surfaces are smooth. The minimum value of u for which the block will reach the top of the wedge is

A block of mass m is pushed towards the movable wedge of mass M and height h , with a velocity v_(0) . All surfaces are smooth . The minimum value of v_(0) for which the block will reach the top of the wedge is

A block of mass m is pushed towards a movable wedge of mass nm and height h , with a velocity u . All surfaces are smooth. The minimum value of u for which the block will reach the top of the wedge is

The block B starts from rest and slides on the wedge A which can move on a horizontal surface, Neglecting friction, determine (a) the acceleration of wedge, (b) the acceleration of the block relative to the wedge.