A cubical block rests on a plane of `mu= sqrt(3)` . The angle through which the plane be inclined to the horizontal so that the block just slides down will be -

A cubical block rests on an inclined plance of mu = (1)/sqrt(3) . Determine the angle at which the block just slides down the incline .

A cubical block rests on an inclined plane with four edges horizontal.If mu = 1/sqrt3 determine the angle when the block just slides down the plane.

A block of mass m rests on a rough inclined plane. The coefficient of friction between the surface and the block is µ. At what angle of inclination theta of the plane to the horizontal will the block just start to slide down the plane?

A block of mass m rests on a rough inclined plane. The coefficient of friction between the surface and the block is µ. At what angle of inclination theta of the plane to the horizontal will the block just start to slide down the plane?

A block mass 'm' is placed on a frictionless inclined plane of inclination theta with horizontal. The inclined plane is accelerated horizontally so that the block does not slide down. In this situation vertical force exerted by the inclined plane on the block is:

It takes a block twice as long to slide down a plane incline at 45^(@) to the horizontal as it would take for it to slide down the same plane had the plane been frictionless. Colculate the coefficient of friction between block and inclined plane.