For the reaction `A+B hArr C`, the rate constants for the forward and the reverse reactions are `4xx10^(2)` and `2xx10^(2)` respectively. The value of equilibrium constant K for the reaction would be

For the reaction , A+2B hArr 2C , the rate constant for the forward and the backward reactions are 1xx10^(-4) and 2.5xx10^(-2) respectively.The value of equilibrium constant, K, for the reaction would be :

For the reaction, A(g)+2B(g) hArr 2C(g) , the rate constant for forward and the reverse reactions are 1xx10^(-4) and 2.5xx10^(-2) respectively. The value of equilibrium constant, K for the reaction would be

For the reaction, A(g)+2B(g) hArr 2C(g) , the rate constant for forward and the reverse reactions are 1xx10^(-4) and 2.5xx10^(-2) respectively. The value of equilibrium constant, K for the reaction would be

For the reaction, A_(g) + 2B_(g) iff 2C_(g) , the rate constants for the forward and the reverse reactions are 1 xx 10^-4 and 2.5 xx 10^-2 respectively. The value of equilibrium constant, K for the reaction would be

For the reversible reaction, A+BhArrC , the specific reaction rates for forward and reverse reactions are 1.25xx10^(3) "and" 2.75xx10^(4) respectively. The equilibrium constant for the reaction is:

For the reversible reaction, A+BhArrC , the specific reaction rates for forward and reverse reactions are 1.25xx10^(3) "and" 2.75xx10^(4) respectively. The equilibrium constant for the reaction is:

For an equilibrium reaction, the rate constants for the forward and the backward reaction are 2.38xx10^(-4) and 8.15xx10^(-5) , respectively. Calculate the equilibrium constant for the reaction.

For an equilibrium reaction, the rate constants for the forward and the backward reaction are 2.38xx10^(-4) and 8.15xx10^(-5) , respectively. Calculate the equilibrium constant for the reaction.

The rate constans of forward and backward reactions are 8.5 xx 10^(-5) and 2.38 xx 10^(-4) respectively. The equilibrium constant if