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A nucleus ""^(220)X at rest decays emitt...

A nucleus `""^(220)X` at rest decays emitting an `alpha`-particle . If energy of daughter nucleus is 0.2 `MeV`, Q value of the reaction is

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During alpha-decay , a nucleus decays by emitting an alpha -particle ( a helium nucleus ._2He^4 ) according to the equation ._Z^AX to ._(Z-2)^(A-4)Y+._2^4He+Q In this process, the energy released Q is shared by the emitted alpha -particle and daughter nucleus in the form of kinetic energy . The energy Q is divided in a definite ratio among the alpha -particle and the daughter nucleus . A nucleus that decays spontaneously by emitting an electron or a positron is said to undergo beta -decay .This process also involves a release of definite energy . Initially, the beta -decay was represented as ._Z^AX to ._(Z+1)^AY + e^(-)"(electron)"+Q According to this reaction, the energy released during each decay must be divided in definite ratio by the emitted e' ( beta -particle) and the daughter nucleus. While , in alpha decay, it has been found that every emitted alpha -particle has the same sharply defined kinetic energy. It is not so in case of beta -decay . The energy of emitted electrons or positrons is found to vary between zero to a certain maximum value. Wolfgang Pauli first suggested the existence of neutrinoes in 1930. He suggested that during beta -decay, a third particle is also emitted. It shares energy with the emitted beta particles and thus accounts for the energy distribution. When a nucleus of mass number A at rest decays emitting an alpha -particle , the daugther nucleus recoils with energy K . What is the Q value of the reaction ?

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