A block tied between identical springs i...

A block tied between identical springs is in equilirium. If upper spring is cut, then the acceleration of the nlock just after cut is `5 ms^(1)` Now if instead of upper string lower spring is cut, then the acceleration of the block just after the cut will be (Take `g=10 m//s^(2)`).

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A block tied between identical springs is in equilibrium. If upper spring is cut, then the acceleration of the block just after cut is 5 ms^(1) Now if instead of upper string lower spring is cut, then the acceleration of the block just after the cut will be (Take g=10 m//s^(2) ).

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A block is attached with an ideal spring and string, and is in equilibrkum as shown in Figure. The acceleration of the block just after breaking the string is a_(1) and just after breaking the spring is a_(2) . Then

A block tied between identical springs is in equilirium. If upper spring is cut, then the acceleration of the nlock just after cut is `5 ms^(1)` Now if instead of upper string lower spring is cut, then the acceleration of the block just after the cut will be (Take `g=10 m//s^(2)`).

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