A bullet of mass x moves with a velocity y, hits a wooden block of mass z, at rest and gets embedded in it. After collision if the wooden block with bullet in it moves the velocity is

A bullet of mass 'x' moves with a velocity y , hits a wooden block of mass z at rest and gets embedded in it. After collision, the wooden block and bullet moves with a velocity

A bullet of mass m moving with velocity v strikes a block of mass M at rest and gets embedded into it. The kinetic energy of the composite block will be

A bullet of mass m moving with velocity v strikes a block of mass M at rest and gets embedded into it. The kinetic energy of the composite block will be

A bullet of mass m, moving with a velocity u hits a wooden block of mass M and gets embedded. Assuming that the wooden block can move freely, show that, the loss of kinetic energy =1/2 (mM)/(m+M) u^2 .

A 50 g bullet moving with velocity 10 m / s strikes a block of mass 950 g at rest and gets embedded in it. The loss in kinetic energy will be

A bullet of mass a moving with a velocity b is made to hit a target of mass c and got embedded into it .Find the velocity of the final system.