The mass defect in a nucleus is `3.5 "amu"`. Then the binding energy of the nucelus is

If the mass defect of ""_(4)^(9)X is 0.09 a.m.u. then the binding energy per nucleon is (1 a.m.u= 931.5 MeV)

Define mass defect of a nucleus. Define binding energy of nucleus.

If the mass defect of ""_(4)^(9)X is 0.099 a.m.u. , then binding energy per nucelon is (1 a.m.u, 931.5 MeV)

The mass defect for the nucleus of helium is 0.0303 a.m.u. What is the binding energy per nucleon for helium in MeV ?

The mass defect for the nucleus of helium is 0.0303 a.m.u. What is the binding energy per nucleon for helium in MeV ?

The energy required to separate all the nucleons inside a nucleus is called binding energy of the nucleus. Write an expression for binding energy in terms of mass defect

The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u.= 931 MeV)

The atomic mass of B^(10) is 10.811 amu . Find the binding energy of B^(10) nucleus . The mass of electron is 0.0005498 amu. The mass of proton is m_(p) = 1.007276 amu . The mass of neutron is m_(n) = 1.008665 amu.