A particle moves in a straight line and its velocity v at time t seconds is given by `v=(6t^(2)-2t+3)` cm/sec. Find the distance travelled by the particle during the first 5 second after the start.

A particle starts from the origin and moves along a straight line. If the velocity of the particle at time t seconds be 10t cm/s, find the distance traversed during first 4 seconds after the start.

A particle moves in a straight line and its velocity v (in cm/s ) at time t (in second ) is 6t^(2) - 2t^(3) , find its acceleration at the end of 4 seconds.

Velocity of a particle moving along a straight line at any time 't' is give by V = cos((pi)/(3)t) . Then the distance travelled by the particle in the first two seconds is :

Velocity of a particle moving along a straight line at any time 't' is give by V = cos((pi)/(3)t) . Then the distance travelled by the particle in the first two seconds is :

A particle starts from the origin and moves along a stright line If the velocity of the particle at time t seconds 10t cm/s then find the distance traversed during fist seconds after the start.

A particle moves in a straight line from origin. Its velocity time curve is shown. Find the distance of particle at the =8sec. From the origin and the distance travelled by the particle during first 8 seconds.

A particle moves in a straight line from origin. Its velocity time curve is shown. Find the distance of particle at the =8sec. From the origin and the distance travelled by the particle during first 8 seconds.