Which reaction is helpful in locating the position of double bond in alkenes ?

What is ozonolysis and how is it useful in locating the position of double bond in an alkene? How would you detect the presence of double bond in an unknown compound?

Give a method for identifying the position of double bond in alkene.

The alkenes have pi -bonds which make them highly reactive. These undergo electrophilic addition reactions, Addition of HX to unsymmetrical alkenes gives two products and follow Markovnikov rule and anti- Markovnikov rule. The addition occure through the formation of carbocation in Markovnikov rule and free radicals in anti-Markovnikov zule. The ozonolysis reaction of alkenes helps to locate the position of double bond. Write the major product in the following reaction: CH_(3)- overset(CH_(3))overset(|)CH-CH=CH_(2) overset(HBr)to

The alkenes have pi -bonds which make them highly reactive. These undergo electrophilic addition reactions, Addition of HX to unsymmetrical alkenes gives two products and follow Markovnikov rule and anti- Markovnikov rule. The addition occure through the formation of carbocation in Markovnikov rule and free radicals in anti-Markovnikov zule. The ozonolysis reaction of alkenes helps to locate the position of double bond. Name the products formed when 2-methylpropene is treated with ozone followed by Zn, H_(2)O .

Lemieux reagent consist of an aqueous solution of sodium periodate (NaIO_(4)) and a trace of KMnO_(4) It is used for locating the position of double bond in an alkene. During the reaction, the alkene is first oxidised to cis-diol which upon cleavage with sodium peroxide gives aldehydes and ketones (similar to ozonolysis). Hot solution of acidic or alkaline KMnO_(4) can also be used for locating double bond by observing the products which are ketones or carboxylic acids. Position of triple bond can be identified by similar process. An alkene on treatment with NaIO_(4) , KMnO_(4) "and" Na_(2)O_(2) gives acetone and acetaldehyde. The alkene is :

Lemieux reagent consist of an aqueous solution of sodium periodate (NaIO_(4)) and a trace of KMnO_(4) It is used for locating the position of double bond in an alkene. During the reaction, the alkene is first oxidised to cis-diol which upon cleavage with sodium peroxide gives aldehydes and ketones (similar to ozonolysis). Hot solution of acidic or alkaline KMnO_(4) can also be used for locating double bond by observing the products which are ketones or carboxylic acids. Position of triple bond can be identified by similar process. An alkene on treatment with NaIO_(4) , KMnO_(4) "and" Na_(2)O_(2) gives acetone and acetaldehyde. The alkene is :

The alkenes have pi -bonds which make them highly reactive. These undergo electrophilic addition reactions, Addition of HX to unsymmetrical alkenes gives two products and follow Markovnikov rule and anti- Markovnikov rule. The addition occure through the formation of carbocation in Markovnikov rule and free radicals in anti-Markovnikov zule. The ozonolysis reaction of alkenes helps to locate the position of double bond. Ozonolysis of an alkene 'A' followed by decomposition with water and a reducing agent gave a mixture of two isomers of the formula C_(3)H_(6)O . Give the structure of the alkene and its IUPAC name.

Lemieux reagent consist of an aqueous solution of sodium periodate (NaIO_(4)) and a trace of KMnO_(4) It is used for locating the position of double bond in an alkene. During the reaction, the alkene is first oxidised to cis-diol which upon cleavage with sodium peroxide gives aldehydes and ketones (similar to ozonolysis). Hot solution of acidic or alkaline KMnO_(4) can also be used for locating double bond by observing the products which are ketones or carboxylic acids. Position of triple bond can be identified by similar process. An aromatic hydrocarbon (Y) on treatment with KMnO_(4) with H^(+)//Delta square gives benzoic acid as one of the products. The hydrocarbon (Y) is :

The best method for locating the position of double bond in an unknown alkene is ...............

The alkenes have pi -bonds which make them highly reactive. These undergo electrophilic addition reactions, Addition of HX to unsymmetrical alkenes gives two products and follow Markovnikov rule and anti- Markovnikov rule. The addition occure through the formation of carbocation in Markovnikov rule and free radicals in anti-Markovnikov zule. The ozonolysis reaction of alkenes helps to locate the position of double bond. Predict the major product in the following reaction: CH_(3)-CH=CH_(2) underset((PhCOO)_(2))overset(HBr)to