`4m+6n=54,3m+2n=28` .

4m+3n=18.3m-2n=5

If m and n satisfy the equations, 3m - n = 40 and4m - 2n = 50, then m=….

Solve the following equations by Cramer's method. 4m - 2n =-4, 4m + 3n = 16

If m=- 4 , n=-2 then the value of m^3 - 3m^2 + 3m + 3n + 3n^2 + n^3 is

If sin A + cos A = m and sin^3 A + cos^3A=n , then (1) m^3-3m + n = 0 (2) n^3-3n + 2m=0 (3) m^3-3m + 2n = 0 (4) m3 + 3m + 2n = 0

If sin A + cos A = m and sin^3 A + cos^3A=n , then (1) m^3-3m + n = 0 (2) n^3-3n + 2m=0 (3) m^3-3m + 2n = 0 (4) m^3 + 3m + 2n = 0

If sin A + cos A = m and sin^3 A + cos^3A=n , then (1) m^3-3m + n = 0 (2) n^3-3n + 2m=0 (3) m^3-3m + 2n = 0 (4) m3 + 3m + 2n = 0

Solve the following equations. 4m+3n=18,3m-2n=5

If (4m + 3n)/(4m - 3n) = (7)/(4) use properties of proportion to find : (i) m : n (ii) (2m^(2) - 11n^(2))/(2m^(2) + 11n^(2)) .