AC is the common hypotneus of the right-angled triangels ABC and ADC. Prove that `angle CAD= angle CBD`

ABC and ADC are two right triangles with common hypotenuse AC. Prove that angle CAD = angle CBD.

On the sides AB and AC of triangle ABC, equilateral triangles ABD and ACE are drawn. Prove that : (i) angle CAD = angle BAE (ii) CD = BE

In triangle ABC, AB = AC and the bisector of angle A lt intersects BC at D. Prove that, ( 1 ) triangle ADB = triangle ADC ( 2 ) angle ABC = angle ACB

ABC is a right triangle right angled at C and AC = sqrt3BC . Prove that angleABC= 60^(@) .

CD is direct common tangent to two circles intersecting each other at A and B. The angle CAD + angle CBD is equal to

∆ABC is a right angled triangle right angled at A and AD _|_ BC . Prove that AD^2 = BD.CD .

ABC is a right triangle right-angled at Cand AC=sqrt(3)BC. Prove that /_ABC=60^(@).

ABC is a isosceles right angled triangle, right angled at C. prove that AB^(2) = 2AC^(2)

ABC is a isosceles right angled triangle, right angled at C. prove that AB^(2) = 2AC^(2)