" ड0- यदि "y^(x)=x^(y)" तो "(dy)/(dx)" ज्ञात कीजिये। "

y -x (dy)/(dx) =0

y-x(dy)/(dx)=x+y(dy)/(dx)

y^2+x^2(dy)/(dx)=x y(dy)/(dx)

Solve: y-x(dy)/(dx)=x+y(dy)/(dx)

If sin(x+y) = cos(x-y), then the value of cos^2 x is: यदि sin(x+y) = cos(x-y), तो cos^2 x का मान ज्ञात करें :

If y = x^(5) show that x(dy)/(dx)-5y = 0 .

The solution of y^(5)x+y-x(dy)/(dx)=0 is

- यदि nc8 = nc2, तो n का मान ज्ञात कीजिये ?

(x - y)dy - (x + y) dx = 0