If `(Px)/((b-c))=(Qy)/((c-a))=(Rz)/((a-b))`, then find `Pax+Qby+Rcz`.

if (log a)/(b-c)=(log b)/(c-a)=(log c)/(a-b) then find the value of a^(a)b^(b)c^(c)

STATEMENT-1 : If log (x + z) + log (x -2y +z) = 2 log (x -z) then x,v,z are in H.P. STATEMENT-2 : If p , q , r in AP and (a -x)/(px) = (a-y)/(qy) = (a-z)/(rz) , then x, y, z are in A.P. STATEMENT-3 : If (a + b)/(1 - ab), b, (b + c)/(1 - bc) are in A .P. then a, (1)/(b) , c are in H.P.

STATEMENT-1 : If log (x + z) + log (x -2y +z) = 2 log (x -z) then x,y,z are in H.P. STATEMENT-2 : If p , q , r in AP and (a -x)/(px) = (a-y)/(qy) = (a-z)/(rz) , then x, y, z are in A.P. STATEMENT-3 : If (a + b)/(1 - ab), b, (b + c)/(1 - bc) are in A .P. then a, (1)/(b) , c are in H.P.

a+b+c=6and(1)/(a)+(1)/(b)+(1)/(c)=(3)/(2), then find (a)/(b)+(b)/(c)+(b)/(a)+(b)/(c)+(c)/(a)+(c)/(b)

If (a)/(b+c) + (b)/(c+a) + (c )/(a+b)= 1 find (a^(2))/(b+c) + (b^(2))/(c+a) + (c^(2))/(a+b)= ?

if a+b+c=6 and (1)/(a)+(1)/(b)+(1)/(c)=(3)/(2) then find (a)/(b)+(a)/(c)+(b)/(a)+(b)/(c)+(c)/(a)+(c)/(b)

If (a-x)/(px) = (a-y)/(qy)= (a-z)/(rz) and p, q, r, be in A.P then x,y, z are in

Suppose a' is a fixed real number such that (a-x)/(px)=(a-y)/(qy)=(a-z)/(rz) if p,q,r are in AP then x,y,z all are in