A proton is accelerated through 225 V . Its de Broglie wavelength is

A deutron is accelerated through 100 V, its de Broglie wavelength is

For a proton accelerated through V volts , de Broglie wavelength is given as lambda =

For a proton accelerated through V volts , de Broglie wavelength is given as lambda =

If the de-Broglie wavelength is lambda_(0) for protons accelerated through 100 V, then the de-Broglie wavelength for alpha particles accelerated through the same voltage will be

If the de-Broglie wavelength is lambda_(0) for protons accelerated through 100 V, then the de-Broglie wavelength for alpha particles accelerated through the same voltage will be

A proton accelerated through a potential V has de-Broglie wavelength lamda . Then, the de-Broglie wavelengthof an alpha-particle, when accelerated through the same potential V is

An electron is accelerated through a potential difference of V volt. It has a wavelength lambda associated with it. Through what potential difference an electron must be accelerated so that its de Broglie wavelength is the same as that of a proton? Take massof proton to be 1837 times larger than the mass of electron

An electron of mass 'm', when accelerated through a potential V has de-Broglie wavelength lambda . The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be:

Ana-particle and alpha - protonare accelerated through same p.d. The ratio of de Broglie wavelength of a proton to a-particle is given by