In Young's experiment, the distance between two slit is 0.8 mm and distance of screen from slit is `1.2` m. If the fringe width is `0.79` mm, then the wave length of light will be

In Young's experiment, the distance between two slits is 0.8mm and the distance of the screen from the slit is1.2 m. If the fringe width is 0.79 mm, the wavelength of light used is

In Young's experiment, the dustance between two slit is 08 mm and the distance of the screen from the slits is 80 cm if the fringe width is 0.6 mm , thent eh wavelenghts of light usedis

In Young's double slit experiment, the distance between the two slits is 0.1 mm, the distance between the screen and the slit is 100 cm. if the width of the fringe is 5 mm, then the wavelength of monochromatic light used is

In Young's double slit experiment , the distance between two slits is 0.1 mm . The distance between the screen and slits is 20 cm . If the slit is illuminated by a light of wavelength 5460 overset (@)(A) then the angular position of the first dark fringe is

In Young's double slit experiment, the distance between sources is 1 mm and distance between the screen and source is 1 m . If the fringe width on the screen is 0.06 cm , then lambda =

In a Young's double slit experiment ,the distance between the slits and the screen is 1 m.If the distance between the slits is 5 mm,the fringe width is found to be 0.1 mm.Calculate the wavelength of the light used.