Let `I_(1)` and `I_(2)` be the moment of inertia of a uniform square plate about axes shown in the figure. Then the ratio `I_(1):I_(2)` is

Let I_(1) and I_(2) be the moment of inertia of a uniform square plate about axes APC and OPO respectively as shown in the figure. P is centre of square. The ratio (I_(1))/(I_(2)) moment of inertia is - .

A solid sphere of mass M and radius R is divided into two unequal parts. The first parts has a mass of (7M)/8 and is converted into a uniform disc of radius 2R. The second part is converted into a uniform solid sphere. Let I_(1) be the moment of inertia of the uniform disc about its axis and I_(2) be the moment of inertia of the sphere made from remaining part about its axis. The ratio I_(1)//I_(2) is 140/x . Find the value of x.

In the circuit as shown in figure, the ratio of current i_1//i_2 is

In the circuit as shown in figure, the ratio of current i_1//i_2 is

If I_(1) is the moment of inertia of a thin rod about an axis perpendicular to its length and passing through its centre of mass and I_(2) is the moment of inertia (about central axis) of the ring formed by bending the rod, then the ratio of I_(1) to I_(2) is

If l_(1) is the moment of inertia of a thin rod about an axis perpendicular to its length and passing through its centre of mass and l_(2) is the moment of inertia (about central axis) of the ring formed by bending the rod, then the ratio of I_(1) to I_(2) is