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" (17) "int(sin(x-x))/(sin(x+2))dx...

" (17) "int(sin(x-x))/(sin(x+2))dx

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int(sin(x-a))/(sin(x+a))dx=

int(sin(x+a))/(sin(x-a))dx

int (sin (x-a))/(sin (x-b))dx=

I=int(sin(x+a))/(sin(x-a))dx

(i) int(sin(x-a))/(sin x)dx

" (1) "int(sin x)/(sin(x+a))dx

I=int(sin x)/(sin(x-a))dx

int (sin x)/(sin (x-a))dx

int (sin (x -a))/(sin x) dx =