`d/(dx)(tan^(-1) ((cos x)/(1+sinx))`=

d/(dx){tan^(-1)((cosx)/(1+sinx))}=

At x=(pi)/(4),(d)/(dx)[tan^(-1)((cosx)/(1+sinx))]=

(d)/(dx)[tan^(-1)((sinx)/(1+cosx))]=

d/(dx)(Tan^(-1)(sinhx)) =

(d)/(dx) {Tan ^(-1) ((1+x)/(1- x))}=

(d)/(dx)[tan^(-1)sqrt((1+sinx)/(1-sinx))]=

d/dx(tan^(-1)x) is :

Differentiate each of the following w.r.t. x: (i) tan^(-1)((1-cosx)/(sinx))" "(ii)tan^(-1)((cos x -sinx)/(cosx +sinx))

(d)/(dx) [tan^(-1) ((a-x)/(1+ ax))] is