If Earth has mass nine times and radius twice that of the planet Mars, calculate the velocity required by a rocket to pull out of the gravitational force of Mars. Take escape speed on surface of Earth to be `11.2km//s`

If the earth has mass 9 times and radius twice that of the planet Mars, calculate the minimum velocity required by a rocket to pull out of the gravitational force of Mars. Escape velocity on the surface of the earth in 11.2 km//s

The escape velocity on the surface of earth is 11.2 km/s. If earth has mass 9 times the mass of Mars and radius equal to twice the radius of Mars, calculate the minimum velocity required by a projectile to escape the gravitational field of Mars.

Calculate the minimum speed required by a rocket to pull out of the gravitational force of Mars. Given that the earth has a mass 9 times and radius twice of the planet Mars. Escape speed on the surface of earth is 11.2 km s^(-1) .

Gravitational acceleration on the surface of a planet is (sqrt(6)//11) g, where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is 2/3 times that of the earth. If the escape speed on the surface of the earth is taken to be 11 km*s^(-1) , the escape speed on the surface of the planet in km*s^(-1) will be

Gravitational acceleration on the surface of a planet is (sqrt6)/(11)g. where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is (2)/(3) times that of the earth. If the escape speed on the surface of the earht is taken to be 11 kms^(-1) the escape speed on the surface of the planet in kms^(-1) will be

The mean diameters of Mars and Earth are 6.9 xx 10^3 km and 1.3 xx 10^4 km, respectively. The mass of Mars is 0.11 times Earth's mass. (a) What is the ratio of the mean density (mass per unit volume) of Mars to that of Earth? (b) What is the value of the gravitational acceleration on Mars? (c) What is the escape speed on Mars?