`(1+costheta+isintheta)^(n)+(1+costheta-isintheta)^(n)`

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(1-costheta+isintheta)^(6)

(costheta+isintheta)^(10)+(costheta-isintheta)^(10)

(1+costheta-isintheta)^4 =

((1+costheta+isintheta)/(1+costheta-isintheta))^(n)

(1-costheta+isintheta)/(1+costheta-isintheta)

Find (costheta+isintheta)^n

(1-costheta+isintheta)^8 =

(1-costheta+isintheta)^6 =

(cos3theta+isin3theta)^5/(costheta+isintheta)^6

Prove that (frac(1+costheta+isintheta)(1+costheta-isintheta))^n=cos ntheta+isin ntheta .