`( sin 4 theta - sin 2 theta )/(cos 4 theta + cos 2 theta )=`

sin 7 theta * sin theta+sin11theta * sin 3theta= A) sin 4 theta * sin 10theta B) cos 4 theta * cos 10 theta C) sin 8 theta * sin 4 theta D) cos 8 theta * cos 14 theta

8 sin theta * cos theta * cos 2 theta * cos 4 theta = A) sin 4 theta B) sin 8 theta C) sin 16 theta D) cos 8 theta

Find the value of (sin^4 theta - cos^4 theta)/(sin^2 theta - cos^2 theta)

Prove that ( cos theta + cos 2 theta + cos 3 theta + cos 4 theta)/(sin theta + sin 2 theta + sin 3 theta + sin 4 theta)= cot ""(5theta)/(2).

1 + (cos 2 theta + cos 6 theta)/(cos 4 theta) = (sin 3 theta)/(sin theta).

The value of (1-2 sin^2 theta cos^2 theta )/(sin^4 theta +cos^4 theta )-1 is: (1-2 sin^2 theta cos^2 theta )/(sin^4 theta +cos^4 theta )-1 का मान है :

If u = (1 + cos theta) (1+ cos2 theta) - sin theta sin 2theta, v = sin theta (1 + cos2 theta) + sin 2 theta(1 + cos theta), "show that" u^(2) + v^(2) = 4(1 + cos theta) (1 + cos 2theta).

If cos theta =4/5 then sin^2 theta cos theta + cos^2 theta sin theta is equal to :

If f(theta)=|(cos^(2) theta, cos theta sin theta, -sin theta),(cos theta sin theta, sin^(2) theta, cos theta),(sin theta, -cos theta, 0)| then f((pi)/12)=