A mass at the end of a spring executes harmonic motion about an equilibrium position with an amplitude A.Its speed as it passes through the equilibrium position is V.If extended 2A and released, the speed of the mass passing through the equilibrium position will be

The bob of pendulum of length l is pulled aside from its equilibrium position through an angle theta and then released. Find the speed v with which the bob passes through the equilibrium position.

A particle executes simple harmonic motion with frequqncy 2.5Hz and amplitude 2 m . The speed of the particle 0.3 s after crossing, the equilibrium position is

A particle executes simple harmonic motion with frequqncy 2.5Hz and amplitude 2 m . The speed of the particle 0.3 s after crossing, the equilibrium position is

The bob of a simple pendulum of length 1 m is' pulled aside from its equilibrium’ position through an angle 60^@ and released. Calculate the speed at which the bob passes the equilibrium position.

The bob of a pendulum of length l is pulled aside from its equilibrium position through an angle theta and then released. The bob will then pass through its equilibrium position with a speed v, where v equals

A pendulum bob of mass m is displaced through an angle theta from its equilibrium position and then released. What will be the tension in the string when the bob crosses the equilibrium position?

A rod of mass M and length l is suspended freely from its end and it can oscillate in the vertical plane about the point of suspension. It is pulled to one side and then released. It passes through the equilibrium position with angular speed omega . What is the kinetic energy while passing through the mean position?