A bar of mass m and length l is hanging from point A as shown in the figure . If the Young's modulus of elasticity of the bar is Y and area of cross - section of the wire is A, then the increase in its length due to its own weight will be

A bar of mass M and length L is hanging from point S as shown in figure. The Young's modulus of elasticity of the wire is Y and the area of cross-section of the wire is A. (i) Find the stress at x distance from bottom end. (ii) Consider a samll section dx of the bar at a distance x from lowest point of bar. Find elongation (dL) in section dx. (iii) Find total elongation in bar. (iv) Find energy density at x distance from bottom and. (v) Find total elastic potential energy stored in bar.

A bar of mass m and length l is hanging from point A as shown in figure.Find the increase in its length due to its own weight. The young's modulus of elasicity of the wire is Y and area of cross-section of the wire is A.

A bar of mass m and length l is hanging from point A as shown in figure.Find the increase in its length due to its own weight. The young,s modulus of elasicity of the wire is Y and area of cross-section of the wire is A.

A bar of mass m and length l is hanging from point A as shown in figure.Find the increase in its length due to its own weight. The young,s modulus of elasicity of the wire is Y and area of cross-section of the wire is A.

If Y is the Young's modulus of a wire of cross sectional area A, then the force required to increase its length by 0.1% will be

A bar is subjected to axial forces as shown. is the modulus of elasticity of the bar is E and A is it cross-section area. Its elongation will be

A wire of length l and radius r has a weight W and the Young's modulus of elasticity Y. it is suspended vertically from a fixed point. Calculate the increase in length of wire porduced due to its own weight.

A bar is subjected lu axial forces as shown. is the modulus of elasticity of the bar is E and A is it cross-section area. Its elongation will be

The Young's modulus of a wire of length 2m and area of cross section 1 mm^(2) is 2 xx 10^(11) N//m^(2) . The work done in increasing its length by 2mm is

A uniform rod of mass m, length L, area of cross-section A and Young's modulus Y hangs from the ceiling. Its elongation under its own weight will be