`CaCO_(3)(s) hArr CaO(s)+CO_(2)(g)`
For the equilibrium , it is found that
`log K_(p)=8-(6400(K))/(T)`
`T=527^(@)C` if `:`

For CaCO_(3)(s) hArr CaO(s)+CO_(2)(g), K_(c) is equal to …………..

For CaCO_(3)(s) hArr CaO(s)+CO_(2)(g), K_(c) is equal to …………..

The reaction CaCO_(3)(s) hArr CaO(s)+CO_(2)(g) reaches the state of equilibrium when

The reaction CaCO_(3)(s) hArr CaO(s)+CO_(2)(g) reaches the state of equilibrium when

For CaCO_(3) hArr CaO + CO_(2) , at equilibrium log K_p = 8 - (6400)/(T(k)) . Then temperature at which K_(p) = 1 ?

For the reaction CaCO_(3(s)) hArr CaO_((s))+CO_(2(g))k_p is equal to

For the reaction CaCO_(3(s)) hArr CaO_((s))+CO_(2(g))k_p is equal to

For CaCO_(3)(S) hArr CaO(s) + CO_(2) (g), Delta H = + Q at equilibrium. The addition of more CaCO3(s) causes?

For CaCO_(3)(S) hArr CaO(s) + CO_(2) (g), Delta H = + Q at equilibrium. to shift equilibrium towards right,

Consider the reaction CaCO_(3)(s) hArr CaO(s) +CO_(2)(g) in closed container at equilibrium. What would be the effect of addition of CaCO_(3) on the equilibrium concentration of CO_(2) ?