[" 21.संसाकलन विधि टे सिद्ध कीजिए कि "],[" (i) "v=u+at," (ii) "s=ut+(1)/(2)at^(2)]

Find the relation s = ut + frac(1)(2)at^2

सिद्ध कीजिए कि |vecA xx vecB|^(2) + |vecA * vecB|^(2) = (AB)^(2).

Derive following equations for a uniformly accelerated motion : (i) v = u + at (ii) S = ut+(1)/(2) at^(2) (iii) v^(2)= u^(2) +2aS Where the symbols have their usual meanings .

Derive the equations of motion by using Velocity to Time graph. (a) v= u + at (b) s = ut + (1)/(2) at^(2) Where , v= Final velocity of an object . u= Initial velocity of an object . a = Acceleration of an object . t= Time duration .

Vertical rise or fall of a particle under gravity is governed by the equations : (i) v =u +gt, (ii) h = ut + (1)/(2) "gt"^(2) , and (iii) v^(2)= u^(2) +2gh the symbols having their usual meanings. Then for a particle dropped from the top of a tower and falling freely. choose the correct options: (i) The distance covered by it after n seconds is directly proportional to

सिद्ध कीजिए कि 2tan^(-1)sqrt((b)/(a))=cos^(-1)((a-b)/(a+b))

Check the dimensional consistency of the following equations : (i) upsilon = u +at (ii) s = ut +(1)/(2) at^2 (iii) upsilon^2 - u^2 = 2as

Deduce the following relations analytically for a uniformly accelerated motion along at a line, where terms have their usual meanings (i) v=u + at (ii) s= ut + 1/2 at^2 (iii) v^2 =u^2 + 2 as .

Derive dimensionally the relation s = ut +(1)/(2)f t^(2) .