x^(2)e^(x)tan x

Differentiate the following with respect to x. y = x^(2)e^(3x)tan^(-1)x

If f(x)=cos^(2)x*e^(tan x),x in(-(pi)/(2),(pi)/(2)) ,then

lim_(x rarr0)((x^(2)e^(x))/(tan^(2)x))=?

If y = log [ sece^(x^(2)) ] then (dy)/(dx) = (a) 2xe^(x^(2))(tan e^(x^(2))) (b) 2xe^(x^(2))(sec x^(2))(tan e^(x^(2))) (c) x^(2)e^(x^(2))tan e^(x^(2)) (d) e^(x^(2))tan e^(x^(2))

The value of lim_(x rarr0)(sqrt(1+x^(3))-((1-x+(x^(2))/(2))e^(x)))/(tan x-x) is equal to:

Given f(x) = int_(0)^(x)e^(t)(ln sec t - sec ^(2) t ) dt, g(x)= - 2e^(x) tan x Find the area bounded by the curves y = f(x) and y = g(x) between the ordinates x = 0 and x = pi/3

int(1+x+x^(2))/(1+x^(2))e^(tan^(-1)x)dx=

"Given "f(x)=int_(0)^(x)e^(t)(log_(e)sec t- sec^(2)t)dt, g(x)=-2e^(x) tan x, then the area bounded by the curves y=f(x) and y=g(x) between the ordinates x=0 and x=(pi)/(3), is (in sq. units)

"Given "f(x)=int_(0)^(x)e^(t)(log_(e)sec t- sec^(2)t)dt, g(x)=-2e^(x) tan x, then the area bounded by the curves y=f(x) and y=g(x) between the ordinates x=0 and x=(pi)/(3), is (in sq. units)