[" 66.Given "1/a=0.5cm^(-1),R=50" ohm."N=1.0." The cquivilent "],[" conductance of the eloctrolytic cell is "]

Given l//a=0.5 cm^(-1), R= 50 "ohm", N= 1.0. The equivalent conductance of the electrolytic cell is .

Given l//a=0.5 cm^(-1), R= 50 "ohm", N= 1.0. The equivalent conductance of the electrolytic cell is .

At a definite temperature, with the same conductivity cell, the specific conductance of "0.01 N KCl" and "0.01 N NaCl" solutions are "y ohm"^(-1)."cm"^(-1) and "z ohm"^(-1)."cm"^(-1) respectively. If the conductance of KCl solution is "x ohm"^(-1) , what will be the conductance of NaCl solution?

The resistance of 0.1 N solution of acetic acid is 250 ohm , when measured in cell of cell constant 1.15 cm^(-1) . The equivalent conductance (in ohm^(-1) cm^(2) "equiv"^(-1) ) of 0.1 N acetic acid is :

The resistance of 0.1N solution of acetic acid 250 ohm. When measured in a cell constant 1.15 cm^-1 . The equilvalent conductance (in ohm^-1 cm^2 eq^-1 ) of 0.1 N acetic acid is

Resistance of a 0.1 M KCl solution in a conductance cell is 300 ohm and specific conductance of "0.1 M KCl" is 1.33xx10^(-2)" ohm"^(-1)"cm"^(-1) . The resistance of 0.1 M NaCl solution in the same cell is 400 ohm. The equivalent conductance of the 0.1 M NaCl solution ("in ohm"^(-1)"cm"^(2)"/gmeq.") is

Resistance of a 0.1 M KCl solution in a conductance cell is 300 ohm and specific conductance of "0.1 M KCl" is .133xx10^(-2)" ohm"^(-1)"cm"^(-1) . The resistance of 0.1 M NaCl solution in the same cell is 400 ohm. The equivalent conductance of the 0.1 M NaCl solution ("in ohm"^(-1)"cm"^(2)"/gmeq.") is

The resistance of 0.1N solution of formic acid is 200 ohm and cell constant is 2.0 cm^(-1) . The equivalent conductivity ( in Scm^(2) eq^(-1)) of 0.1N formic acid is :