[" प्रश्न ८.यदि वक्र "x^(2/3)+y^(2/3)=a^(2/3)" का अभिलम्ब X-अक्ष से "phi],[" कोण बनाए तो दिखाइए कि "],[y cos phi-x sin phi=a cos2 phi" है। "]

(3 cos phi+cos 3 phi)/(3 sin phi-sin 3 phi)=

If a normal of curve x^(2//3)+y^(2//3)=a^(2//3) makes an angle phi from X-axis then show that its equation is y cos phi -x sin phi = a cos 2phi .

If the normal to the curve x^((2)/(3))+y^((2)/(3))=a^((2)/(3)) makes an angle phi with the x-axis,show that its equation is,y cos phi-x cos phi=a cos2 phi

Prove: (sin phi - cos phi) ^(2) =1 - sin 2 phi.

If x=sec phi-tan phi and y=cos ec phi+cot phi then

If the normal at any point to the curve x^(2//3)+y^(2//3)=a^(2//3) makes an angle phi with the x-axis then prove that the equation of the normal is y cos phi- x sin phi = a cos 2phi .

If x=sec phi-tan phi and y=cos ec phi+cot phi, then

Find int( (3 sin phi-2) cosphi)/(5-cos ^2 phi-4 sin phi) d phi

If the normal at any point on the curve x^(2//3) + y^(2//3) = a^(2//3) makes an angle phi with the x-axis, then prove that the equation of the normal is y cosphi - x sin phi = a cos 2 phi