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In binomial probability distribution, me...

In binomial probability distribution, mean is 3 and standard deviation is `3/2`. Then the value of p is

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I : In a binomial distribution the mean is 2 and the standard deviation is sqrt3 . Then the distribution is ((1)/(4)+(3)/(4))^(16) II : In a binomial distribution , n=5 the sum mean and variance is 1.8. Then the distribution is ((4)/(5)+(1)/(5))^(5)