A thin uniform circular ring is rolling down an inclined plane of inclination `30^(@)` without slipping. Its linear acceleration along the inclined plane will be

A thin uniform circular ring is rolling down an inclined plane of inclination 30^(@) without slipping. Its linear acceleration along the inclined plane is :

A thin uniform circular ring is rolling down an inclined plane of inclination 30^(@) without slipping. Its linear acceleration along the inclined plane is :

A thin uniform circular ring is rolling down an inclined plane of inclination 30^(@) without slipping. Its linear acceleration along the inclined plane is :

Consider a thin uniform circular ring rolling down in an inclined plane without slipping. Compute the linear acceleration along the inclined plane if the angle of inclination is 45'

A thin circular ring rolls down a smooth inclined plane of inclination 30degree without slipping. What is it's linear acceleration in the plane ?

A cylinder is rolling down on a inclined plane of inclination 60^(@) . What is iths acceleration?

A cylinder is rolling down on a inclined plane of inclination 60^(@) . What is iths acceleration?

A cylinder rolls down an inclined plane of inclination 30^@ , the acceleration of cylinder is