Find the equation of the plane through the line of intersection of the planes `x + y + z = 1`and `2x + 3y + 4z = 5`which is perpendicular to the plane`x y + z = 0`.

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to x-y+z=0

Find the equation of the plane through the line of intersection of the planes given by the equations x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane given by the equation x - y + z = 0.

Find the equation of the plane through the line of intersection of the planes given by the equations x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane given by the equation x - y + z = 0.

The equation of the plane passing through the line of intersection of the planes x + y + 2z = 1,2x + 3y + 4z = 7, and perpendicular to the plane x - 5y + 3z = 5 is given by:

Find the equation of the plane through the intersection of the planes 2x - 3y + z - = 0 and x - y + z + 1 = 0 and perpendicular to the plane x + 2y - 3z + 6 = 0.